Help would this be divide by two after you solve it regularly??
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OpenStudy (anonymous):
OpenStudy (anonymous):
Cause what I did was I used the equation,
4pir^2
plugged in my numbers
4pi9
multiplied the numbers together and got 36pi and then divided it by two because it is half a circle..
OpenStudy (anonymous):
@xapproachesinfinity
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
you are doing it correctly
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jimthompson5910 (jim_thompson5910):
yes a hemisphere is a half-sphere, so you cut the surface area in half
jimthompson5910 (jim_thompson5910):
actually no wait
you forgot to include the bottom portion (the circular base)
OpenStudy (anonymous):
so ...how do I Include that??
jimthompson5910 (jim_thompson5910):
find the area of the circle with radius 3
OpenStudy (anonymous):
I did have the radius of three
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OpenStudy (anonymous):
cause 3^2 equals nine
jimthompson5910 (jim_thompson5910):
well above you computed the surface area of the top of the hemisphere
now you have to find the base of it
OpenStudy (anonymous):
wouldn't you just have to add the two half's together??
OpenStudy (anonymous):
... wait I am confused, can you write the equation I am suppose to use?
jimthompson5910 (jim_thompson5910):
|dw:1406685498691:dw|
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jimthompson5910 (jim_thompson5910):
There's the hemisphere
you calculated this shaded region (the upper outer shell of the half-sphere)
|dw:1406685540855:dw|