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Mathematics 4 Online
OpenStudy (anonymous):

Help would this be divide by two after you solve it regularly??

OpenStudy (anonymous):

OpenStudy (anonymous):

Cause what I did was I used the equation, 4pir^2 plugged in my numbers 4pi9 multiplied the numbers together and got 36pi and then divided it by two because it is half a circle..

OpenStudy (anonymous):

@xapproachesinfinity

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

you are doing it correctly

jimthompson5910 (jim_thompson5910):

yes a hemisphere is a half-sphere, so you cut the surface area in half

jimthompson5910 (jim_thompson5910):

actually no wait you forgot to include the bottom portion (the circular base)

OpenStudy (anonymous):

so ...how do I Include that??

jimthompson5910 (jim_thompson5910):

find the area of the circle with radius 3

OpenStudy (anonymous):

I did have the radius of three

OpenStudy (anonymous):

cause 3^2 equals nine

jimthompson5910 (jim_thompson5910):

well above you computed the surface area of the top of the hemisphere now you have to find the base of it

OpenStudy (anonymous):

wouldn't you just have to add the two half's together??

OpenStudy (anonymous):

... wait I am confused, can you write the equation I am suppose to use?

jimthompson5910 (jim_thompson5910):

|dw:1406685498691:dw|

jimthompson5910 (jim_thompson5910):

There's the hemisphere you calculated this shaded region (the upper outer shell of the half-sphere) |dw:1406685540855:dw|

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