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Mathematics 15 Online
OpenStudy (samsan9):

Consider the function . y=2x-3/x+4 what is the equation of the vertical asymptote?

OpenStudy (samsan9):

i got x=-4 from the denominator

OpenStudy (samsan9):

@cram

OpenStudy (anonymous):

let me try something @TSwizzle please help sam i cant right now

OpenStudy (anonymous):

Is This A Essay Question?

OpenStudy (anonymous):

thanks juss alot i apretiate it

OpenStudy (anonymous):

umm i dont think so hey sam honey is it

OpenStudy (samsan9):

samuel :)

OpenStudy (anonymous):

awesome i love your name samuel

OpenStudy (anonymous):

Actually The Answer For Is x=-4 And Lol This Is Funni xP

OpenStudy (anonymous):

yeah lol

OpenStudy (samsan9):

lol oh it is XD someone else was helping but left so i didn't really know hahha

OpenStudy (anonymous):

Haha Oh Wow Alright Then x3

OpenStudy (anonymous):

ok samuel you good

OpenStudy (samsan9):

yeah lol

OpenStudy (anonymous):

thank you samuel

OpenStudy (samsan9):

do you think you could help me with this part of the question?

OpenStudy (anonymous):

i can try lol

OpenStudy (samsan9):

What kind of additional asymptote does this function have, horizontal or oblique?

OpenStudy (anonymous):

horizontal

OpenStudy (samsan9):

What is the equation of this additional asymptote?

OpenStudy (anonymous):

Heres The 4 Answers Ik What Your Doing ~ Part I: x = -4 This is the value that will make the denominator of the equation equal to zero, causing an asymptote. Part II: horizontal The degree of the numerator is the same as that of the denominator. This always indicates a horizontal asymptote. Part III: y=2 To find the horizontal asymptote, you take the limits of the equation. In cases like this, the limit is the coefficient of the first term in the numerator divided by the coefficient of the first term in the denominator. Part IV: Draw in some characteristics of the graph. This means dotted lines at y=2 and x=-4. Also, points at the x- and y-intercepts, which here are (-1.5, 0) and (0, -0.75). Then simply connect the dots, keeping in mind the asymptotes.

OpenStudy (anonymous):

Got It?

OpenStudy (samsan9):

yes i do thank you and where did you get that answer?

OpenStudy (anonymous):

Just Searched It Up On Google xD

OpenStudy (samsan9):

wow it was on there the whole time :o

OpenStudy (anonymous):

wow really juss

OpenStudy (anonymous):

Yes Lol Your Welcome Though xD ahahaha

OpenStudy (anonymous):

hmmm thank you lol

OpenStudy (anonymous):

xD WELCOMEE <3

OpenStudy (anonymous):

lmao

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