Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Help please

OpenStudy (mrnood):

It's difficult to know how to guide you here - can you explain the difficulty you are having? You can see that f(1) and f(2) are correct in all the answers (by comparing with the table) So you must concentrate on how to calculate f(n) when n>2 Look at the formulae in all the answers for whne n=3 for example. See if the formula produces the result which is in the table. If it does then check for n=4,5 &6 Only one of the answers provides the correct results for all values of n

OpenStudy (anonymous):

im lost

OpenStudy (anonymous):

@MrNood oh and sorry my mom had called me to do someething

OpenStudy (mrnood):

look at the table If n=3 tell me what f(n-2) is please?

OpenStudy (anonymous):

f(6)

OpenStudy (mrnood):

not - that's not it. If n= 3 what does (n-2) =? (So what does f(n-2) = (look at the table)

OpenStudy (anonymous):

f(1)

OpenStudy (mrnood):

correct - and what is the value of f(1) from the table

OpenStudy (anonymous):

1

OpenStudy (anonymous):

???

OpenStudy (mrnood):

Good - so you can see how to read the values from the table. Now look at the answers. Take the second answer It says that for n>2 then f(n) = f(n -1) + f(n - 2); n > 2 SO using the same method as you did above, right down f(n -1) + f(n - 2) when n=3

OpenStudy (anonymous):

f(3)=f(2)+(1);n>2

OpenStudy (mrnood):

And what is the value of f(2)+f(1) ?

OpenStudy (anonymous):

f(3)

OpenStudy (mrnood):

I want the actual numerical values - read them from the table..

OpenStudy (anonymous):

what do you mean

OpenStudy (mrnood):

Go back to the earlier posts - you told me f(n-2) is f(1) (when n=3) you then looked in the table to see that f(1) is 1 now do the same to find the value of f(2)+f(1)

OpenStudy (anonymous):

no

OpenStudy (anonymous):

its not the same

OpenStudy (mrnood):

The initial posts were just to show you how to read the table. Now - look at the table and find the value of f(2) look at the table and find the value of f(1) Then calculate the value of f(2)+f(1)

OpenStudy (anonymous):

f(3)

OpenStudy (mrnood):

you are not reading the table. Let's try again What is the value of f(6)?

OpenStudy (anonymous):

oh thats what you ment 32

OpenStudy (mrnood):

OK - good look at the table and find the value of f(2) look at the table and find the value of f(1) Then calculate the value of f(2)+f(1)

OpenStudy (anonymous):

3

OpenStudy (mrnood):

OK - that's correct Now - the second answer says f(n) = f(n -1) + f(n - 2) Is this true when n=3? (you have done nearly ALL the work above for this....)

OpenStudy (anonymous):

f(3)=f(2)+f(1)

OpenStudy (anonymous):

so yes

OpenStudy (mrnood):

you wrote down above that f(2)+f(1)=3 that is correct But what is f(3)?

OpenStudy (anonymous):

when you add f(1)+f(3) thats f(3)=f(3)

OpenStudy (anonymous):

so n is 3

OpenStudy (anonymous):

wait im lost what do you mean whats f(3)

OpenStudy (mrnood):

I'm really sorry - but you seem to need to revise the meaning of the table and the equations given in the answers. The table lists the values of n (1-6) and the CORRESPONDING values of f(n) I asked you what f(6) was and you correctly answered 32 I asked you what f(3) is and you are confused...

OpenStudy (anonymous):

2?

OpenStudy (anonymous):

you good im really slow

OpenStudy (mrnood):

Tell me how you (correctly) got f(6) = 32

OpenStudy (anonymous):

the table

OpenStudy (mrnood):

so tell me what f(3) is

OpenStudy (anonymous):

2

OpenStudy (mrnood):

OK - correct so remember f(3)=2 NOW go back to just now what is (f3-1)+f(3-2)

OpenStudy (anonymous):

f(3)

OpenStudy (mrnood):

what is the VALUE of (f3-1)+f(3-2) (look at the table...) (you already worked this out)

OpenStudy (anonymous):

so its f(2-1)+f(2-2)?

OpenStudy (mrnood):

Sorry to have to go now - you really are some way from being able to solve this for yourself. Please take a look at your text book, or speak to your tutor. There are some basic concepts you need to work on before you can answer this. Please don't give up ... good luck

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!