Question

solve for z

Answer 1

\[7-\sqrt{3z+2}=4\]

Answer 2

anyone?

Answer 3

Wait.....I'll ask @SolomonZelman to help you...

Answer 4

may i?

Answer 5

Sure...

Answer 6

sure?

Answer 7

take 7 to other side of =

Answer 8

z = 7/3
z = 11/3
none

Answer 9

that would be 4+7?

Answer 10

11

Answer 11

Are you going to transpose?

Answer 12

me?

Answer 13

no it will be 4-7
because now its + so when it jumps over = it will be -

Answer 14

oh right

Answer 15

im lost.

Answer 16

next step is to remove square root sign

Answer 17

11/3?

Answer 18

Wait she's lost....

Answer 19

severly

Answer 20

\[-\sqrt{3z+2}\]

Answer 21

wait wait wait dont be so fast

Answer 22

\[=4-7\]

Answer 23

I know....

Answer 24

\[-\sqrt{3z+2}=4-7\] right?

Answer 25

look
first step take +7 to other side of =
\[\sqrt{3x+2}=4-7\]
got it

Answer 26

where's the negative sign of the squre root?

Answer 27

@K.Jay is this ur question or @EngrChong 's question because ur not participating in it

Answer 28

Its hers.... Just trying to learn from it....

Answer 29

And she posted another question...

Answer 30

ok

Answer 31

She'll see your solutions....

Answer 32

i see it but im serverly confused..... Sorry

Answer 33

Just look at @sheelo_mughal solution...

Answer 34

- sign will be removed because when \[\sqrt{}\]jumps over = it will be\[\left( \ \right)^2\] oh god u made me confuse

Answer 35

@K.Jay do u have answer options for this?

Answer 36

oh sorry...

Answer 37

yes.

Answer 38

can u tell me?

Answer 39

z = 7/3
z = 11/3
none

Answer 40

sorry my internet connection was lost

Answer 41

\[7-\sqrt{3z+2}=4\]
\[\sqrt{3z+2}=4-7\]
\[\sqrt{3x}=4-7-2\]
\[\sqrt{x}=4-7-2/3\]
\[x=\left( 4-7-2 \div( 3)^2 \right)\]

Answer 42

@K.Jay

Answer 43

@EngrChong

Answer 44

thanks guys!

Answer 45

ur welcome