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OpenStudy (anonymous):
create a quadratic equation with two real zeros
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OpenStudy (anonymous):
fan and medal
OpenStudy (xapproachesinfinity):
okay let's say the zeros are 3 and -2 alright!
OpenStudy (anonymous):
ok
OpenStudy (xapproachesinfinity):
We know that the general form of a quadratic equation is like this
ax^2+bx+c
OpenStudy (anonymous):
which part of that would be the zeros?
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OpenStudy (xapproachesinfinity):
the zero are the solution the equation ax^2+bx+c=0
otherwise known as x-intercepts?
OpenStudy (anonymous):
so a(3)^2 + b(-2) + c?
OpenStudy (xapproachesinfinity):
if 3 and -2 are zeros for a certain quadratic function
then we know that it will be factored like this (x-3)(x+2)
OpenStudy (anonymous):
oh
OpenStudy (xapproachesinfinity):
No not just follow okay
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OpenStudy (xapproachesinfinity):
if we solve (x-3)(x+2)=0 we would get x-3=0 or x+2=0
right?
OpenStudy (anonymous):
right
OpenStudy (xapproachesinfinity):
this what we mean by zeros
OpenStudy (xapproachesinfinity):
So our function would be like f(x)=(x-3)(x+2) since those are the two solution to f(x)=0
OpenStudy (xapproachesinfinity):
Do you agree?
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OpenStudy (anonymous):
yes :) i understand now
OpenStudy (xapproachesinfinity):
Okau, we are not done yet. we still need to write it like ax^2+bx+c
OpenStudy (xapproachesinfinity):
f(x)=(x-3)(x+2) you can use FOIL
OpenStudy (xapproachesinfinity):
Can you do that?
OpenStudy (anonymous):
what is FOIL?
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OpenStudy (xapproachesinfinity):
okay let me draw you what it is
OpenStudy (anonymous):
ok
OpenStudy (xapproachesinfinity):
|dw:1406732706692:dw|
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