Determine two pairs of polar coordinates for the point (4, 4) with 0° ≤ θ < 360°
use x=rcos(theta) and y=rsin(theta) from here u can determine theta can u do it?
not quite, what is r again?
look in cartesian coordinate system there are mainly two coordinates which is (x,y) and in polar system the coordinates are expressed as (r,theta) caresian x is expressed as \[x=rcos(\theta)\] and cartesian y is expressed as \[y=rsin(\theta)\] make sense?
yes
so \[\frac{ x }{ y }=rcos \theta/r \sin \theta\] so \[\tan \theta=y/x\]and then\[\theta=\tan^{-1} (\frac{ y }{ x })\] ok so far?
yes
so now just put x=4 and y=4 so whats the value of theta?
pi/4
good so theta is evaluated now we need to calculate r
for r -- find \[x^2+y^2\] can u do it?
32
yes so it would be equal to r^2 now ok with this?
yes
\[x^2+y^2=r^2(\cos^2 \theta+\sin ^2 \theta)=r^2\] \[r=\sqrt{x^2+y^2}=\sqrt{32}=4\sqrt{2}\] got this?
yes
so the polar coordinates are \[(4\sqrt{2},\frac{ \pi }{ 4 })\]
ok
good :)
But the answers are in degrees, so do we need to convert?
yeah u can write (pi/4) equal to 45 degree
ok, thanks
yw!
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