Question

square root of 10 and 6 divided by square root of 3

Answer 1

\[\sqrt{10*6} / \sqrt{3}
or
\sqrt{10+6}/\sqrt{3}\]

Answer 2

@Purplerainbowcherry its square root of 10 and square root of 6 its two radicals at the top then divided by square root of 3

Answer 3

\[\frac{ \sqrt{10}+\sqrt{6} }{ \sqrt{3} }\] ?

Answer 4

yes

Answer 5

okay i got the answer

Answer 6

\[\sqrt{10} = \sqrt{2} * \sqrt{5}\]
\[\sqrt{6} = \sqrt{2} * \sqrt{3}\]
so basically : \[\frac{ \sqrt{2}*\sqrt{5}+\sqrt{2}*\sqrt{3} }{ \sqrt{3} } \]

and as such you can take \[\sqrt{2}\] out since it is is common :
\[\frac{ \sqrt{2}(\sqrt{5}+\sqrt{3}) }{ \sqrt{3} } \]

next, you multiply by \[\sqrt{3} \] in the denominator and the numerator in order to rationalise
so : \[\frac{ \sqrt{2}(\sqrt{5}+\sqrt{3}) }{ \sqrt{3} } * \frac{ \sqrt{3} }{ \sqrt{3} }\]

Answer 7

for the denominators , you get square root of 9 which is 3, so your denominator becomes 3

Answer 8

for the numerators, you simply multiply and simplify and get :
\[\sqrt{30} + 3\sqrt{2} \]