Question

what are the zeros of the function f(x) = x^2 - x - 12
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x^2 + x -12

Answer 1

\[f(x)=\dfrac{x^2-x-12}{x^2+x-12}\]
is it right?

Answer 2

first off, you must have the condition for f(x) defined by solving denominator. I mean you need know the roots of denominator. It says \(x\neq 3\) and \(x\neq -4\). If you don't know how to get it, let me know

Answer 3

then, to get f(x) =0, we need numerator =0--> set \(x^2-x-12 =0\) solve for x, you will have
x=4 and x =-3
Those roots satisfied the condition above, therefore, they are solution.