When 7.0 mol Al react with 8.5 mol HCl, what is the limiting reactant and how many moles of AlCl3 can be formed?

2 Al + 6 HCl “yields”/ 2 AlCl3 + 3 H2

Al is the limiting reactant, 7.0 mol AlCl3 can be formed

HCl is the limiting reactant, 2.8 mol AlCl3 can be formed

Al is the limiting reactant, 3.5 mol AlCl3 can be formed

HCl is the limiting reactant, 8.5 mol AlCl3 can be formed

I chose the last one. Is it right? (please someone help. I really want to get this one right)

Question

When 7.0 mol Al react with 8.5 mol HCl, what is the limiting reactant and how many moles of AlCl3 can be formed? 

2 Al + 6 HCl  “yields”/ 2 AlCl3 + 3 H2

 Al is the limiting reactant, 7.0 mol AlCl3 can be formed

 HCl is the limiting reactant, 2.8 mol AlCl3 can be formed

 Al is the limiting reactant, 3.5 mol AlCl3 can be formed

 HCl is the limiting reactant, 8.5 mol AlCl3 can be formed

I chose the last one. Is it right? (please someone help. I really want to get this one right)

anonymous · Answer

Can someone just help me out a little?

antonio_xx2 · Answer

divide the amount of moles of each individual species by it's own coefficient in the balanced equation:

moles/coefficient= normalized moles

which ever one has the least amount is the limiting reactant.

anonymous · Answer

umm

anonymous · Answer

wait so what's the answer?

anonymous · Answer

@antonio_xx2 I saw someone give the exact answer to someone else and it doesnt make sense to me.