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Mathematics 8 Online
OpenStudy (anonymous):

A phone company worker needs to know the height of a cell tower, so he decides to use a 2 m pole and shadows cast by the sun, as shown in the diagram. Both shadows end at point B. What is the height of the tower? (Points : 5) 30 m 32 m 36 m 40 m

OpenStudy (anonymous):

OpenStudy (antonio_xx2):

2 is to 3; as h is to (45+3)

OpenStudy (anonymous):

what? @antonio_xx2

OpenStudy (antonio_xx2):

similar triangles have similar ratios

OpenStudy (anonymous):

@mrgenius

OpenStudy (antonio_xx2):

can u explain this to her @ash2326

OpenStudy (ash2326):

@maguihajji I will draw the figure here, so that we can understand the question.|dw:1406746600239:dw| C is the cell tower, P is the pole of height 2 meters. Do you follow this?

OpenStudy (anonymous):

yeah

OpenStudy (ash2326):

Ok let's make this a triangle, so that we use properties of triangle|dw:1406746907414:dw| So we have big triangle ADEB

OpenStudy (ash2326):

and small triangle PEB. Do you follow this

OpenStudy (anonymous):

yeah

OpenStudy (ash2326):

ok if we look at angles CDB and PEB, can you tell me their value in degrees?

OpenStudy (anonymous):

omg i dont know are they a right triangle what is happening

OpenStudy (ash2326):

yes, you are right. they are straight and therefore right angles. So we can angle CDB= angle PEB. Now look closely at angle DBC and EBP, can you find the relation b/w them?

OpenStudy (anonymous):

ummm i dont know they share the same angle?

OpenStudy (ash2326):

Yes the two triangles have a common angle and therefore equal angles. Recall that we already have two angles as right angles therefore equal What can you tell me about the third angle of both the triangles

OpenStudy (anonymous):

its equal too?

OpenStudy (ash2326):

You check and confirm

OpenStudy (anonymous):

what? check?how? im so confused jesus

OpenStudy (ash2326):

it's easy, recall that sum of angles of a triangle is 180

OpenStudy (ash2326):

so for both triangles sum will be equal 180=180 we can also write 180 in term of sum of all three 90+Angle1+ Angle 3= 90+ Angle 1 + Angle 3 now angle 1 is same for both already which is the common angle so third angle for both will be?

OpenStudy (anonymous):

ummmm 45........?

OpenStudy (ash2326):

I just want to know the relation between third angle of both the triangles not the value

OpenStudy (anonymous):

but what does that have to do with the tower?

OpenStudy (ash2326):

if we know the relation between angles, then only we can apply formula to find the height of tower. It's like if you don't know if a rectangle is square, how you can find its area if you have only one side given???

OpenStudy (anonymous):

omg im so confused right now

OpenStudy (ash2326):

oh ok, I will make it clear. We have this 180= 180

OpenStudy (ash2326):

LEFT side 180 degrees I will write as sum of angles of bigger triangle and right side as sum of smaller triangle

OpenStudy (ash2326):

|dw:1406748087880:dw|

OpenStudy (ash2326):

\[\angle DAB+\angle ABD+\angle BDA=\angle EPB +\angle PBE+\angle BEP\] We know \[\angle BDA=\angle BEP=90\] so \[\angle DAB+\angle ABD+90=\angle EPB +\angle PBE+90\] do you follow till now?

OpenStudy (anonymous):

i think so

OpenStudy (ash2326):

and \[\angle ABD= \angle PBE\] so we are left with \[\angle DAB+\angle ABD+90=\angle EPB +\angle PBE+90\] Let's cancel the common terms \[\angle DAB+\cancel {\angle ABD}+\cancel {\cancel {90}}=\angle EPB +\cancel{\angle PBE}+\cancel {\cancel{90}}\] so the third angles of both the triangles are equal

OpenStudy (anonymous):

so what does that mean? whats the answer

OpenStudy (ash2326):

We will be able to find the answer now. So the two triangles are similar. that means their sides are in same ratio so \[\frac{AD}{PE}=\frac{DB}{EB}\] where AD is height of tower also/ Do you follow?

OpenStudy (anonymous):

i do follow however i dont know how to do ratios

OpenStudy (ash2326):

I will help with ratios. Can you look in the diagram and tell the values of PE, DB, EB

OpenStudy (anonymous):

pe - 2 db - 48? eb- 3?

OpenStudy (anonymous):

is the answer 32?

OpenStudy (ash2326):

Good, you are right. Let's plugin these values in the formula. \[\frac{AD}{PE}=\frac{DB}{EB}\] \[\frac{AD}{2}=\frac{48}{3}\]

OpenStudy (ash2326):

yes, you are right, how did you find?

OpenStudy (anonymous):

i cross multiplied omg thank you so so so so so so so so sooooo muchhh <3 life saver

OpenStudy (ash2326):

You're welcome, did you understand the solution?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

solve it using Pythogoras theorem, i guess you have got the solution by now. Sorry couldnt be on

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