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Mathematics 8 Online
OpenStudy (anonymous):

divide (20x^3-35x+18) divide (5x-5)... i dont get it

OpenStudy (anonymous):

divide with?

OpenStudy (anonymous):

do you mean \[(20x^{3}-35x+18)\div(5x-5)\]?

OpenStudy (anonymous):

idk thats all the problem gives

OpenStudy (anonymous):

its polynomial division

OpenStudy (anonymous):

and no its to the 3rd

OpenStudy (anonymous):

can you take a pic and attach the file?

OpenStudy (anonymous):

ok... whats the keys for screenshot

OpenStudy (anonymous):

i have no idea

OpenStudy (anonymous):

ok its (20x^3-35x+18)/(5x-5)

OpenStudy (anonymous):

so it's like the equation i typed up earlier?

OpenStudy (anonymous):

yah but the 20 is to the 3rd

OpenStudy (anonymous):

I wrote that... \[20x ^{3}\] or do you mean \[(20x)^{3}\]

OpenStudy (anonymous):

20x to the third

OpenStudy (anonymous):

the first or second one, because that makes a huge difference in the outcome of this problem. Twenty x to the third is exactly how you say both of the choices

OpenStudy (anonymous):

first

OpenStudy (anonymous):

okay, now we're getting somewhere. So, the equation is like this right now \[\frac{ (20x ^{3}-35x+18) }{ 5x-5 }\] are you familiar with the concept of factoring?

OpenStudy (anonymous):

yah

OpenStudy (anonymous):

so, you now need to factor the top part of the equation. Before we go anyfurthur is this a multiple choice question or just a fill in the answer question?

OpenStudy (anonymous):

multiple choice

OpenStudy (anonymous):

choices?

OpenStudy (anonymous):

4x^2-4x+3+(3/5x-5) 4x^2+4x-3+/(3/5x=5) 4x^2+4x-3-(3/x) 4x^2-4x+3-(3/5x-5)

OpenStudy (anonymous):

okay...those are really weird choices. it cant be the second one since you can't divide by an equal sign, so that leaves the other three left

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so what you need to do is factor the top part of the equation

OpenStudy (anonymous):

and due to process of elimination it probably isn't going to be D

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

... hello?

OpenStudy (anonymous):

yes? I thought you were factoring the top of the formula

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