divide (20x^3-35x+18) divide (5x-5)... i dont get it
divide with?
do you mean \[(20x^{3}-35x+18)\div(5x-5)\]?
idk thats all the problem gives
its polynomial division
and no its to the 3rd
can you take a pic and attach the file?
ok... whats the keys for screenshot
i have no idea
ok its (20x^3-35x+18)/(5x-5)
so it's like the equation i typed up earlier?
yah but the 20 is to the 3rd
I wrote that... \[20x ^{3}\] or do you mean \[(20x)^{3}\]
20x to the third
the first or second one, because that makes a huge difference in the outcome of this problem. Twenty x to the third is exactly how you say both of the choices
first
okay, now we're getting somewhere. So, the equation is like this right now \[\frac{ (20x ^{3}-35x+18) }{ 5x-5 }\] are you familiar with the concept of factoring?
yah
so, you now need to factor the top part of the equation. Before we go anyfurthur is this a multiple choice question or just a fill in the answer question?
multiple choice
choices?
4x^2-4x+3+(3/5x-5) 4x^2+4x-3+/(3/5x=5) 4x^2+4x-3-(3/x) 4x^2-4x+3-(3/5x-5)
okay...those are really weird choices. it cant be the second one since you can't divide by an equal sign, so that leaves the other three left
ok
so what you need to do is factor the top part of the equation
and due to process of elimination it probably isn't going to be D
ok
... hello?
yes? I thought you were factoring the top of the formula
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