if you have an antifreeze solution that is 2.35M ethylene glyco (C2H6O2 -molar mass-62.1g/mol) in water. How many mL of this solution would you need if you want to have 93.0 g of ethylene glycol?

Question

joannablackwelder · Answer

2.35 M means 2.35 mol/L.

joannablackwelder · Answer

Can you find how many moles of ethylene glycol is in 93g?

joannablackwelder · Answer

@zaxoanl?

zaxoanl · Answer

93g / 62.1g   i got 1.5 mol ethylene

zaxoanl · Answer

then i use  2.35M = 1.5mol/L   i got .64L        .64*1000= 640mL   not sure if that is correct

joannablackwelder · Answer

I get really close to that. Probably just rounding difference.