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Chemistry 10 Online
OpenStudy (zaxoanl):

if you have an antifreeze solution that is 2.35M ethylene glyco (C2H6O2 -molar mass-62.1g/mol) in water. How many mL of this solution would you need if you want to have 93.0 g of ethylene glycol?

OpenStudy (joannablackwelder):

2.35 M means 2.35 mol/L.

OpenStudy (joannablackwelder):

Can you find how many moles of ethylene glycol is in 93g?

OpenStudy (joannablackwelder):

@zaxoanl?

OpenStudy (zaxoanl):

93g / 62.1g i got 1.5 mol ethylene

OpenStudy (zaxoanl):

then i use 2.35M = 1.5mol/L i got .64L .64*1000= 640mL not sure if that is correct

OpenStudy (joannablackwelder):

I get really close to that. Probably just rounding difference.

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