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OpenStudy (anonymous):
Any idea on what this means?
Fill in the blank to make the expression a perfect square.
v^2-4v+?
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OpenStudy (anonymous):
4
OpenStudy (anonymous):
It would be 2. c:
OpenStudy (anonymous):
you take half of the -4, then square it
OpenStudy (anonymous):
so that's -2^2...which is 4 (this is called completing the square)
OpenStudy (anonymous):
@haiimawesome is right
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OpenStudy (anonymous):
I'm sorry everybody, but do you mind each explaining your answer?
OpenStudy (anonymous):
haiimawesome's explanation is right.
OpenStudy (anonymous):
I'll bet she is but I would like to understand it (I'm not doubting you guys!)
OpenStudy (anonymous):
to complete the square, you take the -4, and divide it by two. Then, you square that answer. THis gives you 4
OpenStudy (anonymous):
Ok following you so far.
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OpenStudy (anonymous):
so that makes the equation: v^2 - 4v + 4
OpenStudy (anonymous):
So you are saying that v^2-4v+4 is a perfect square?
OpenStudy (anonymous):
that's it!
OpenStudy (anonymous):
how does that make it a perfect square? Just curious to find out the "why" in the how
OpenStudy (anonymous):
But you are doing a great job explaining the process :)
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OpenStudy (kirbykirby):
It's a perfect square because you can factor it into a single "squared" term.. i.e.
\(v^2-4v+4 = (v-2)^2\)
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