Question

An observer (O) spots a plane flying at a 42° angle to his horizontal line of sight. If the plane is flying at an altitude of 15,000 ft., what is the distance (x) from the plane (P) to the observer (O)?

A right triangle is shown with one angle marked 42 degrees, one side marked x and the height marked 15000 feet.

10,035 feet

16,648 feet

20,188 feet

22,417 feet

Answer 1

got picture?

Answer 2

idk how tp post it

Answer 3

use the blue button of [Attach File] below this text

Answer 4

ok got it ;)

Answer 5

\(\bf sin(\theta)=\cfrac{opposite}{hypotenuse}\implies hypotenuse=\cfrac{opposite}{sin(\theta)}\)

Answer 6

so would i put 1500o over x because that is the hypotenuse

Answer 7

well..yes... but you would want to find "x".... so \(\bf sin(\theta)=\cfrac{\frac{opposite}{(15,000)}}{\frac{hypotenuse}{x}}\implies \frac{hypotenuse}{x}=\cfrac{\frac{opposite}{(15,000)}}{sin(\theta)}\)

Answer 8

recall, your hypotenuse is "x" and your angle is 42 degrees and your opposite side is 15,000

Answer 9

\(\bf sin(\theta)=\cfrac{opposite}{hypotenuse}\to hypotenuse=\cfrac{opposite}{sin(\theta)}\to x=\cfrac{15,000}{sin(42^o)}\)

Answer 10

ok im starting to understand but idk how to type this into the calculator i know the functions i just dont know how to place it

Answer 11

42 and then press [sin] button
make sure your calculator is in Degree mode

Answer 12

I think that plane is 16659.188 feet away - see picture:

http://www.triangle-calculator.com/?what=rt&a=A%3D42+a%3D15000&submit=Solve

Answer 13

how about using -> https://desmos.com/calculator

Answer 14

https://www.google.com/search?client=opera&q=15000/sin(42+degrees)&sourceid=opera&ie=utf-8&oe=utf-8&channel=suggest&gws_rd=ssl

Answer 15

ok i did what u said but the numbers cant be rite ill try desmos hold on
and thank you for taking time to help me

Answer 16

ok i got it ill try one omo and can u check it for me pls?

Answer 17

well. you can always post anew... in case I dunno, someone else may and we can revise each other :)

Answer 18

ok thanks ; )

Answer 19

A bird (B) is spotted flying 6,000 feet from a tower (T)). An observer (O) spots the top of the tower (T)) at a distance of 9,000 feet. What is the angle of depression from the bird (B) to the observer (O)?

Right triangle OTB is shown. Side OT labeled 9000 and side TB is labeled 9000. The angle B is labeled x degrees.

33.69°

41.81°

48.18°

56.31°

Answer 20

would i use tangent