Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

What is the graph of the function f(x) = x^2-7x+12/x-3

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

@sylbot dont give up on meeeee

OpenStudy (here_to_help15):

i wont give up = )

OpenStudy (anonymous):

yay! i missed you :D

OpenStudy (here_to_help15):

: D

OpenStudy (solomonzelman):

The graph is a line, do you know why @andy11 ?

OpenStudy (solomonzelman):

Hint: `x²-7x+12 = (x-3)(x-4)`

OpenStudy (here_to_help15):

ughh

OpenStudy (solomonzelman):

Okay fine

OpenStudy (solomonzelman):

The graph is a line, because \(\normalsize\color{blue}{ x^2-7x+12 }\) factors into \(\normalsize\color{blue}{ (x-3)(x+4) }\), and thus `(x-3)` cancels on top and bottom.

OpenStudy (solomonzelman):

The result you get is, \(\normalsize\color{blue}{ f(x)=x+4 }\)

OpenStudy (solomonzelman):

(pretty much) the same as `y=x+4` and you know what that will look like. If not, I can demonstrate 2 very easy ways to do it.

OpenStudy (solomonzelman):

I'll be back if I am on after you reply.

OpenStudy (anonymous):

hey thank you so much for explaining it. i can take it from here thanks again!

OpenStudy (solomonzelman):

Just wanted to add SHIFTS: f(x)= ∛x ⇒ f(x)= ∛(x \(\normalsize\color{blue}{ +~\rm{c} }\) ) , c units left. f(x)= ∛x ⇒ f(x)= ∛(x \(\normalsize\color{blue}{ -~\rm{c} }\) ) , c units right. f(x)= ∛x ⇒ f(x)= ∛(x )\(\normalsize\color{blue}{ -~\rm{c} }\) , c units down. f(x)= ∛x ⇒ f(x)= ∛(x )\(\normalsize\color{blue}{ +~\rm{c} }\) , c units up. You can also tell, that y=x+4 is the same as y=x, but shifted 4 units up.

OpenStudy (solomonzelman):

Anytime.... !

OpenStudy (anonymous):

ok thank you and the answer that i got was the last attachment i posted

OpenStudy (solomonzelman):

yes, that is correct :)

OpenStudy (anonymous):

yay! thank you (:

OpenStudy (solomonzelman):

You welcome !

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!