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Chemistry 17 Online
OpenStudy (superhelp101):

Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimental data provided. A + B products Trial [A] [B] Rate 1 0.30 M 0.25 M 1.2 × 10-2 M/min 2 0.30 M 0.50 M 4.8 × 10-2 M/min 3 0.60 M 0.50 M 9.6 × 10-2 M/min

OpenStudy (superhelp101):

@aaronq ?

OpenStudy (anonymous):

K=7.111 \[R=KA ^{3}B ^{2}\]

OpenStudy (superhelp101):

are you saying that R=K A^3 B^2 is the rate ?

OpenStudy (anonymous):

The reaction is third order A and second order B

OpenStudy (superhelp101):

i know that trial 3 is twice as trial 1

OpenStudy (aaronq):

thats not right. Note trial 1 and trial 2, gives you \([B]^2\) and trial 2 and trial 3 gives \([A]^1\)

OpenStudy (superhelp101):

@aaronq so what do you say the rate is ?

OpenStudy (aaronq):

at what point?

OpenStudy (superhelp101):

well the question says Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimental data provided. so idk what point is that ?

OpenStudy (aaronq):

so we figured out the rate law, you just need the value for k - the rate constant.

OpenStudy (superhelp101):

K=7.111

OpenStudy (superhelp101):

what is next ?

OpenStudy (aaronq):

thats all they asked for

OpenStudy (superhelp101):

ohh so how do i explain this ?

OpenStudy (superhelp101):

oh nvm you already told me that ! thanks for helping !!

OpenStudy (superhelp101):

@amematsro thanks too!

OpenStudy (aaronq):

no problem!

OpenStudy (anonymous):

no problem

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