Find the first six terms of the sequence.
a1 = -8, an = 5 • an-1
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OpenStudy (anonymous):
-8, -40, -200, -1000, -5000, -25,000 is what i'm thinking
OpenStudy (anonymous):
@jdoe
OpenStudy (anonymous):
@SolomonZelman
OpenStudy (solomonzelman):
You got the common ratio and the first term.
OpenStudy (solomonzelman):
YES
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OpenStudy (solomonzelman):
The terms are all correct.
OpenStudy (solomonzelman):
You need just the terms, or maybe also their sum ?
OpenStudy (anonymous):
just the first 6 terms.
OpenStudy (solomonzelman):
Okay
OpenStudy (anonymous):
do you think you could help me with other problems on this thread?
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OpenStudy (solomonzelman):
Yes, sure.
OpenStudy (solomonzelman):
You are either very good at getting used to new websites such as openstudy, or you had a different account before. (I would think the first one )
OpenStudy (anonymous):
i am new.
OpenStudy (anonymous):
Find an equation for the nth term of the arithmetic sequence.
a10 = 32, a12 = 106
OpenStudy (solomonzelman):
At first you need to find the difference. But by equation do you mean to find the \(\large\color{blue}{ a_n=a_1+d(n-1) }\) or \(\large\color{blue}{ a_n=a_{n-1}+d }\) ?
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OpenStudy (solomonzelman):
\(\large\color{blue}{ a_{12}=a_{10}+2d }\)
OpenStudy (solomonzelman):
the last one is to find the difference.
OpenStudy (anonymous):
the 1st one you wrote
OpenStudy (solomonzelman):
Okay, from \(\large\color{blue}{ a_{12}=a_{10}+2d }\) can you find the difference?
OpenStudy (anonymous):
d=37
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OpenStudy (anonymous):
is that right?
OpenStudy (solomonzelman):
(106-32)÷2=37... correct.
OpenStudy (solomonzelman):
Then, for \(\large\color{blue}{ a_n=a_1+d(n-1) }\)
OpenStudy (solomonzelman):
You need to find a1, can you do that?
OpenStudy (anonymous):
no, could you help me?
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