Question

Find the margin of error when p = 83% and n = 300. Round your answer to the nearest hundredth.

Answer 1

Hmm, don't you need a confidence level to determine the margin of error?

Answer 2

I think so

Answer 3

Weird... well, I would assume a 95% confidence level (that's the standard one I think), which would make the margin of error
\[1.96\sqrt\frac{p(1-p)}{ n}\]
but that depends on the confidence level, like I mentioned.

Answer 4

is 1.96 the answer?

Answer 5

For the margin of error? No. The margin of error (*assuming* 95% confidence) would be
\[1.96\sqrt\frac{.83(1-.83)}{300}\]

Answer 6

can you calculate that

Answer 7

Really?

Answer 8

http://www.wolframalpha.com/input/?i=1.96*Sqrt%5B.83%281-.83%29%2F300%5D

Answer 9

thanks