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OpenStudy (anonymous):
PLEASE HELP! Prove: tan2 θcos2 θ + cos2 θ = 1. You must show all work
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OpenStudy (zzr0ck3r):
hint:
\(\tan^2(\theta)\cos^2(\theta)=\frac{\sin^2(\theta)}{\cos^2(\theta)}\cos^2(\theta)=\frac{\sin^2(\theta)}{\cancel{\cos^2(\theta)}}\cancel{\cos^2(\theta)}\)
OpenStudy (anonymous):
Is sin^2 T = 1??
OpenStudy (zzr0ck3r):
another hint:
There was a dude named Pythagoras, and he and his friends did some pretty cool stuff.
OpenStudy (anonymous):
Haha I understand, what do I put into the pythagorean thereom?
OpenStudy (zzr0ck3r):
correct
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OpenStudy (anonymous):
So sin^2 T = 1 is the final portion of this answer?
OpenStudy (zzr0ck3r):
\(\tan^2(\theta)\cos^2(\theta)+\cos^2(\theta)=\frac{\sin^2(\theta)}{\cos^2(\theta)}\cos^2(\theta)+\cos^2(\theta)=\\\frac{\sin^2(\theta)}{\cancel{\cos^2(\theta)}}\cancel{\cos^2(\theta)}+\cos^2(\theta)=\sin^2(\theta)+\cos^2(\theta)= \ \huge ?\)
OpenStudy (anonymous):
1?
OpenStudy (anonymous):
@zzr0ck3r
OpenStudy (zzr0ck3r):
correct, that is the Pythagorean theorem \(\cos^2(x)+\sin^2(x) = 1\) for all \(x\).
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OpenStudy (anonymous):
Thank you so much @zzr0ck3r
OpenStudy (zzr0ck3r):
np.
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