Two spheres have a volume ratio of 27:8. What is the ratio of their radii?
I don't get how to do this.
@JoannaBlackwelder
I think that the radii would be the ratio of the cube roots of the volumes.
Let say the volume of big sphere is V1 and the volume of small one is V2, and we have \(\dfrac{V1}{V2}=\dfrac{27}{8}\) ok so far? not finish yet, but I need know you got it or not.
@claritamontano I am waiting for your reply to step up.
Yeah I get it,
We have formula to find the volume of the sphere. It says V= \(\dfrac{4}{3}\pi r^3\) where r is radius of the sphere, so that, we have \(V1= \dfrac{4}{3}\pi r_1^3\) and \(V2= \dfrac{4}{3}\pi r_2^3\) so far so good?
Yeah.
so, just plug in V1/V2 = 27/8 you have \(\dfrac {r_1^3}{r_2^2}=\dfrac{27}{8}\) or \(\dfrac{r_1}{r_2}= \dfrac{3}{2}\)
ah I get it so my answer would now be 3:2
got it? just algebra \(\dfrac {r_1^3}{r_2^2}=(\dfrac{r_1}{r_2})^3=\dfrac{27}{8}=(\dfrac{3}{2})^3\) which gives us the ratio of the radii is 3/2
yeah! thanks wait not 3:2 or is that the same thing?
the same 3:2
okay thanks I get it!
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