Question

I will give anyone a medal if they can help me! It will be posted below.

Answer 1

\[\frac{ m^2+mn-2n^2 }{ m^3+m^2n }\times \frac{ m^2+3mn+2n^2 }{ m }\]

Answer 2

Have you try to factor any of them by yourself yet?

Answer 3

yes and im not sure if its right. Ill put it up

Answer 4

Ok

Answer 5

\[\frac{ mn(m-2n }{ m^2(m+n) }\times \frac{ (m+n)(m+2n) }{ m }\]

Answer 6

is that right @nikato

Answer 7

They're all right except m^2 +mn-2n^2

Answer 8

You should know it should look like
(m _ _n)(m_ _n)
Now you have to figure if its +/- and the coefficient for n

Answer 9

And in thi case, you are looking for two numbers that multiply and get -2 but their sum is 1

Answer 10

Would my final answer be \[\frac{ m+2n)^2(m-n) }{m^3 }\]

Answer 11

Yes

Answer 12

Thank you!

Answer 13

You're welcome