Question

Quadrilateral RSTU has vertices R (-3, 1) , S (-2, 3) , T (2, 3) , and U (3, 1). If you translate the quadrilateral four units down, what are the vertices of R'S'T'U'?

R' (-3, -3) , S' (-2, -1) , T '(2, -1) , and U' (3, -3)

R' (1, 1) , S' (2, 3) , T '(6, 3) , and U '(7, 1)

R' (-7, 1) , S' (-6, 3) , T '(-2, 3) , and U '(-1, 1)

R (-3, 3) , S (-2, 1) , T (2, 1) , and U (3, 3)
@Squirrels @tkhunny

Answer 1

Don't do anything to the x-values.

This discards the second and third.

Subtract 4 from all the y-values.

Narrow it down, yet?

Answer 2

is it 1?

Answer 3

You tell me. If you subtract 4 from all the y-values, do you reproduce the points listed in 1)?

Answer 4

yes?

Answer 5

Then, why do you doubt? Mark it and move on.

Answer 6

sorry im just not sure if im right

Answer 7

What happens when triangle ABC is translated t units parallel to the x-axis?

The points of A'B'C' are given as (x +t, y+t).

The points of A'B'C' are given as (x, y+t).

The points of A'B'C' are given as (x-t, y-t).

The points of A'B'C' are given as (x +t, y).

Answer 8

This is one of the deficiencies of mathematics education. Students don't actually know they are supposed to be learning confidence. :-) Hang in there. Stop believing you can't do it. You'll get it with patience and earnest effort.

Answer 9

Ill try! thank you, i know i dont believe enough in my self

Answer 10

Still not posting on a new thread? :-)
This is sufficiently closely related.

Nothing changes for y-values. The first three are immediately eliminated.