Given that f(x)=x^3+kx^2-2x+1 has reamainder k when it is divided by (x-k),find possible values of k @Callisto
Use the remainder theorem. When f(x) is divided by x=m and have a remainder n, we have f(m) = n In this case, f(x) is divided by k and the remainder is k, so, what is m and n?
f(k)=k
k^3+k(k)^2-2k+1=k k^3+k^3-3k+1=0 2k^3-3k+1=0 like this @Callisto
Yes. Now, try factor theorem to factorize the expression on the left.
nt sure..
By educated guess, try x=1...
f(1)=k
Sorry... Consider f(k) = 2k^3-3k+1, what is f(1)?
, try x=1..
Ehmmmm.... If g(k) = 2k^3-3k+1, what is g(1)?
g(1)=0 so, (x-1) is a factor of g(k)
(k-1) is a factor of g(k), there is no x in the function g. Now, divide g(k) by k-1 to get the other factor. Can you do it?
|dw:1406797390324:dw| not sure..
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