Question

sound wave x has intensity 10^12 times greater than that of sound wave Y. By how much is the amplitude of x greater than the amplitude of Y?

Answer 1

Now I know Intensity is proportional to the square of amplitude but I don't know how to apply that

Answer 2

use
\[I \alpha A^2\rightarrow \frac{ I_1 }{ I_2 }=\frac{ A_1^2 }{ A_2^2 }\]

Answer 3

where I=intensity and
A=amplitude

Answer 4

I have never seen that notation...

Answer 5

\[A _{1}^{2}\]

Answer 6

Is not something I've been introduced to

Answer 7

Intensity is proportional to the square of amplitude
u have to use this relation

Answer 8

Oh right of course so I = A^2 so A = I^0.5 giving 10^(12*0.5) giving A = 10^6

Thanks!