sound wave x has intensity 10^12 times greater than that of sound wave Y. By how much is the amplitude of x greater than the amplitude of Y?

Question

anonymous · Answer

Now I know Intensity is proportional to the square of amplitude but I don't know how to apply that

sidsiddhartha · Answer

use 
$$I \alpha A^2\rightarrow \frac{ I_1 }{ I_2 }=\frac{ A_1^2 }{ A_2^2 }$$

sidsiddhartha · Answer

where I=intensity and
A=amplitude

anonymous · Answer

I have never seen that notation...

anonymous · Answer

$$A _{1}^{2}$$

anonymous · Answer

Is not something I've been introduced to

sidsiddhartha · Answer

Intensity is proportional to the square of amplitude
 u have to use this relation

anonymous · Answer

Oh right of course so I = A^2 so A = I^0.5 giving 10^(12*0.5) giving A = 10^6

Thanks!