What volume will 1.25 liters of carbon dioxide occupy at 50.0°C if the pressure changes from 0.865 atm to 0.820 atm? 1.76 .567 1.18 1.32
\(P_1V_1=P_2V_2\)
is 1.25 v1?
it can be either, you just have to group the first set of conditions together (assign them the same subscript)
ok so i got 1.18 as my answer?
thats not right
post what you did
ok p1= .865 v1=1.25 p2=.820 and v2=50.0
\(V_2=50\)? but that's what you're solving for \(V_2\). More importantly, 50\(^oC\) is the temperature..
o ok so i would just multiply pressure and then divide by v1
i dont know what you mean
i would multiply p1 and p2 and then when i get my answer i would divide by v1
my new answer is .567
did you follow the formula i posted?
yes
ok let's use the formula as aronqq as stated above.... btw don't focus on the temperature because it's constant and that'ts why we won't include it in the formula
ok
I dont think so, there is no possible way you can multiply the pressures together with it. Try setting up the formula with the correct values first
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