What volume will 1.25 liters of carbon dioxide occupy at 50.0°C if the pressure changes from 0.865 atm to 0.820 atm?
1.76
.567
1.18
1.32
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OpenStudy (aaronq):
\(P_1V_1=P_2V_2\)
OpenStudy (anonymous):
is 1.25 v1?
OpenStudy (aaronq):
it can be either, you just have to group the first set of conditions together (assign them the same subscript)
OpenStudy (anonymous):
ok so i got 1.18 as my answer?
OpenStudy (aaronq):
thats not right
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OpenStudy (aaronq):
post what you did
OpenStudy (anonymous):
ok p1= .865 v1=1.25
p2=.820 and v2=50.0
OpenStudy (aaronq):
\(V_2=50\)?
but that's what you're solving for \(V_2\).
More importantly, 50\(^oC\) is the temperature..
OpenStudy (anonymous):
o ok so i would just multiply pressure and then divide by v1
OpenStudy (aaronq):
i dont know what you mean
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OpenStudy (anonymous):
i would multiply p1 and p2 and then when i get my answer i would divide by v1
OpenStudy (anonymous):
my new answer is .567
OpenStudy (aaronq):
did you follow the formula i posted?
OpenStudy (anonymous):
yes
OpenStudy (asib1214):
ok let's use the formula as aronqq as stated above.... btw don't focus on the temperature because it's constant and that'ts why we won't include it in the formula
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OpenStudy (anonymous):
ok
OpenStudy (aaronq):
I dont think so, there is no possible way you can multiply the pressures together with it.
Try setting up the formula with the correct values first