Question

Solve the following system of equations:
-2x + y = 1
4x + y = -1




1)(3, 1)
2)(-1, 3)
3)(-1, -3)
4)(1, 3)

Answer 1

Are you familiar with the elimination method?

Answer 2

yeah im just not very good at it

Answer 3

Ok first thing you want to do is multiply -1 to the bottom equation so you can "eliminate" the bottom variable.
\[-1(-2x+y=1)\]
\[2y-y=1\]

Answer 4

Oops that was the top equation, but it doesn't really matter which one you do
Now you can cancel out the y variables
\[2x-y=-1\]\[4x+y=-1\] \[6x=2\]

Answer 5

simply subtract both of these..you will get

-6x=2
=>x=-1/3
now reput it in any of given eq you will get..

say eq1 =>>-2(-1/3)+y=1
=>2/3+y=1
=>y=1-2/3
=>y=(3-2)/3
=>y=1/3

you will get.

(x,y)=(-1/3,1/3)

so your eq have some mistake,,,if answer is from those choices..!!!

Answer 6

multiply equation 1 by number 2 which gives equation as 2(-2x + y = 1) =>-4x + 2y =2
add this equation to the second one 4x + y = -1
you get 3y=1 => y=1/3 and by replacing y in any equation u get x=-1/3

Answer 7

the options are wrong check again

Answer 8

@princeharryyy i have already mention that eq have some deviation from orignal values..!!1now it has been clear that eq are in -correct..

Answer 9

ugh...

Answer 10

@zaibali.qasmi question isn't wrong only the answers options are wrong )) hehe !!! enjoy !!! brother

Answer 11

their right i copied and pasted them right off the parctice sheet

Answer 12

may be they have given the wrong options in your practice sheet....
it's okay the answer is(-1/3,1/3) its 100% correct sweetie....

Answer 13

sweetie... );;

Answer 14

huh?