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Mathematics 9 Online
OpenStudy (anonymous):

PLEASE HELP! I'll give medals & fan. Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4^(-x) and y = 2^(x + 3) intersect are the solutions of the equation 4-x = 2^(x + 3). (4 points) Part B: Make tables to find the solution to 4^(-x) = 2^(x + 3). Take the integer values of x between -3 and 3. (4 points) Part C: How can you solve the equation 4^(-x)= 2^(x + 3) graphically? (2 points)

OpenStudy (anonymous):

@xvddedge

OpenStudy (anonymous):

Thanks for mentioning me! And here wait @imastudent1

OpenStudy (anonymous):

no problem lol. can you help me?

OpenStudy (anonymous):

I'll try. It's sort of hard to explain.

OpenStudy (anonymous):

you don't have to explain to me. i just need the answer.

OpenStudy (anonymous):

i think its b not sure but um try b

OpenStudy (anonymous):

its not multiple choice lol you're supposed to explain the asnwer.

OpenStudy (anonymous):

@superhelp101

OpenStudy (anonymous):

@campbell_st

OpenStudy (anonymous):

Well I'm not really sure what to explain but I am sure if you ask a mathlete for help the shall know

OpenStudy (campbell_st):

well both equations are equal to y. The point of intersection is where 2 curves share a common point. so you can then equate the expressions in x, since they are both equal to x. (b) Table of values y = 4^-x y = 2^(x + 3) x: -3 : -2: -1: 0 : 1 : 2 : 3 x: -3 : -2: - 1: 0 : 1 : 2 : 3 --------------------------------- -------------------------- y: 64 : 16: 4 : 1 : 1/4 : 1/16 : 1/64 y : 1 : 2 : 4: 8: 16 : 32 :64 to find the solutions rewrite the 1st equation with a base of 2 so you should be able to see the point of intersection. (c) just plot the ordered pairs or use https://www.desmos.com/calculator to graph the curves

OpenStudy (anonymous):

What do I put for part A?

OpenStudy (anonymous):

@campbell_st

OpenStudy (campbell_st):

Its is the point that is part of both curves... and the x value is independent... both equations are equal to y, so you can equate them and then attempt to solve then to see if there is a solution.

OpenStudy (anonymous):

oh okay thank you :)

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