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OpenStudy (anonymous):

An image of the moon is focused onto a screen using a converging lens of focal length f= 36.3 cm. The diameter of the moon is 3.48×106 m, and its mean distance from the earth is 3.85×108 m. What is the diameter of the moon's image?

OpenStudy (anonymous):

Can you find the distance of the image of the moon form the lens ?

OpenStudy (anonymous):

I have tried this so many times i am honestly confused as where to start now

OpenStudy (anonymous):

You start calculating the distance of the image of the moon form the lens. Use \[\frac{1}{Focal \ length} = \frac{1}{Object\ distance} + \frac{1}{Image\ distance}\] and then calculate magnification using \[m = -\frac{Image\ distance}{Object\ distance}\]

OpenStudy (anonymous):

But magnification is also given by \[m = \frac{size \ of \ image}{size\ of\ object}\]

OpenStudy (anonymous):

so 1/.363m -1/3.85E8

OpenStudy (anonymous):

Correct

OpenStudy (anonymous):

=-3.85E-8

OpenStudy (anonymous):

then take that and divide by 3.85E8?

OpenStudy (anonymous):

You should get: image distance = 36.3 cm (focal length)

OpenStudy (anonymous):

This is because you can treat the object at a very large distance such that 1/ 3.85E8 = 0 compared to 1/.363 !

OpenStudy (anonymous):

I am confused so the answer is 1/.363?

OpenStudy (anonymous):

Invert it to get image distance. See the formula again. \[\frac{1}{0.363} = 0+ \frac{1}{Image\ distance}\]

OpenStudy (anonymous):

image distance is equal to .363

OpenStudy (anonymous):

so how do I find the diameter?

OpenStudy (anonymous):

Find the magnification using the formula I mentioned above.

OpenStudy (anonymous):

Oh my gosh thatnk you!

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