Question

If 0.98 moles of BaCl2 are dissolved in enough water to make a 1.2-liter solution, what is the resulting molarity

Answer 1

0.98/1.2= 0.816M

Answer 2

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Answer 3

\(\sf \large Molarity=\frac{No.~of~moles~of~solute}{Volume~of~solution~in~litre}\)

Answer 4

Here,
moles of solute=0.98
Volume of solution=1.2 L

\(\sf \large Molarity=\frac{0.98}{1.2}\)