how would I solve this p(t) = –log10 t is p was 0

Question

anonymous · Answer

Its for this assignment

anonymous · Answer

So you're solving
$$0=-\log_{10}t$$
for $t$.
$$0=\log_{10}t$$
Raise both sides to the 10th power:
$$10^0=10^{\log_{10}t}$$
Any nonzero base to the zeroth power is 1. For the right side, use the property that $\log_bb^a=a$:
$$1=t$$

anonymous · Answer

but if you raise both sides to the tenth power wouldn't it be $$0^{10}$$

anonymous · Answer

@SithsAndGiggles

anonymous · Answer

Sorry, I used the wrong words there... I meant take both sides as the powers of 10. Sorry for the confusion

anonymous · Answer

its fine so I would use the change of base formula

anonymous · Answer

No you wouldn't need that here. You can directly solve for $t$ in both equations of part (a). It's just a matter of removing the logarithm by using exponentiation.

anonymous · Answer

but if you raise both sides to the tenth power would It be this I'm sorry I'm not trying to argue with you or anything but I just don't seem to get it