The area of the sector formed by the 110 degree central angle is 50 units squared. What is the radius of this circle??
You need the formula for the area of a sector of a circle.
Solve the following for r: \[\frac{110 \pi r^2}{360}=50 \]\[r=30 \sqrt{\frac{2}{11 \pi }} \]
Here's The Pic That Goes To My Question
A complete cicle is 360 degrees and it's area is pi r^2. 110/360 pi r^2 is the area of 110 degrees of the same circle.
@gswag98 This is a problem that needs a formula. You need to either memorize the formula or know where to find it. Then you need to know how to use it. The formula for the area of a sector of a circle is: \(A = \dfrac{\theta}{360^o}\pi r^2\) The Greek letter \(\theta\) (called theta) represents the measure of the central angle that intercepts the arc. In your case, theta = 110 deg. You know the area: A = 50. You are looking for r. The first step is to write the formula, which we have done above. Now replace all the dimensions you were given (theta and A) \(50 = \dfrac{110^o}{360^o}(3.14159) r^2\) \(50 = 0.95993r^2\) \(\dfrac{50}{0.95993} = r^2\) \(r^2 = 52.087\) Now take square root of both sides: \(r = 7.22\)
is that 7.22 rounded to two decimal plces
Yes.
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