How to find the average rate of change in functions?
Average rate of change of a function between two points is the secant through the two points.
its delta y over delta x
So, my two points are (10, 16.13) and (3, 13.12) I do..\[\frac{ 16.13 }{ 10 }?\]
sorry I was a bit caught up on the other.... the average between two point is the speeds divided by the points in it
This is still the other one, I just tried to break it down into something smaller so I could just do it myself.
(10, 16.13) and (3, 13.12) <----- does that mean the rate is 13.12 at point 3 and 16.13 at point 10?
ohh yes, I see is the same =)
Well, thats just a graphed point on the function \[f(n) = 12(1.03)^n\]
ok so \(\large { f(n)=12(1.03)^n\quad \begin{cases} n=3\\ n=10 \end{cases} \\ \quad \\ \cfrac{f(10)-f(3)}{10-3} }\)
And I solve that?
yeah, its delta y over delta x. How much y changes as a ratio to the change in x. The order doesn't matter. (you can do f(3)-f(10)/3-10 too)
what does delta mean?? /.\
\(\Large \Delta\) is just a notational way to say " the difference between endpoint and start point values"
Oh..?
site is a bit laggy.... thus
but anyhow... for your case the endpoint value is f(10) and the start value is f(3) their difference is f(10) - f(3) and you divide that by however many points are in between, in this case wil be 7, because 10 - 3
So.. \[\frac{ f(7) }{ 7 }?\]
nono, you need to evaluate f(10)-f(3) then divide by 7.
How do you do that..?
evaluate f(10) then evaluate f(3) (do this by typing it into your calculator) then subtract the two values. THEN divide by 7.
\[f(10) = 12(1.03)^{10} = 16.12699655\] \[f(3) = 12(1.03)^{3} = 13.112714\] \[16.12699655 - 13.112714 = 3.01428255\] \[\frac{ 3.01428255 }{ 7 } = 0.430611793\]
yeap
That's my answer? 0.0
yeap that's correct
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