Find the approximate change in T for the function T=4+3u-3u^2 when u is increased by 5% from the value of 2.

Question

aum · Answer

Find $\Large \frac{dT}{du}$
Replace $\Large \frac{dT}{du}$ with $\Large \frac{\Delta T}{\Delta u}$
Substitute, $\Delta u = 0.05, u = 2$ and find the approximate value of $\Delta T$.

sachin00007 · Answer

can u pls tell us the exact answer for the problem @aum

anonymous · Answer

Another approach:
$$u\xrightarrow{\large\text{5% increase}}u+0.05u=1.05u$$
So when $u=2$, you have $1.05u=2.1$.

When $u=2$, you have
$$T=4+3(2)-3(2)^2=-2$$
When $u=2.1$,
$$T=4+3(2.1)-3(2.1)^2=-2.93$$
Find the percent change in the $T$ values.