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Mathematics 13 Online
OpenStudy (jenniferjuice):

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OpenStudy (jenniferjuice):

Felix exclaims that his quadratic with a discriminant of −1 has no real solutions. Felix then puts down his pencil and refuses to do any more work. Create an equation with a negative discriminant. Then explain to Felix, in calm and complete sentences, how to find the solutions, even though they are not real.

OpenStudy (anonymous):

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OpenStudy (anonymous):

0.0 No

OpenStudy (jenniferjuice):

@morningskye123

OpenStudy (anonymous):

lol yes?

OpenStudy (jenniferjuice):

please help lol

OpenStudy (anonymous):

I'm just guessing but this is your exam question? ;)

OpenStudy (jenniferjuice):

maybeeeeeeee

OpenStudy (anonymous):

lol yeah it is. I had the same question

OpenStudy (jenniferjuice):

yesss so could ya help me out?

OpenStudy (anonymous):

Yeah I guess. Let me see if I remember most of the answer. Well, you need to create a q- function that has a negative discriminant

OpenStudy (jenniferjuice):

2x^2 + 1x + 3 = 0

OpenStudy (jenniferjuice):

.?

OpenStudy (jenniferjuice):

And then complete the square.?

OpenStudy (anonymous):

It's not asking that. Do the discriminant formula to see if it has a negative outcome

OpenStudy (anonymous):

And once you have the outcome explain to your mad friend what you can do with negative discriminant

OpenStudy (jenniferjuice):

Okay,so discriminant formula on 2x^2 + 1x + 3 .?

OpenStudy (anonymous):

Yes A=2x^2, B=1x C=3. Plug it into the, I forgot the formula but its the top part of the quardratic formula

OpenStudy (jenniferjuice):

-b(+or-)sqrt(b^2 + 4ac)

OpenStudy (anonymous):

-2^2 +4(2)(3)

OpenStudy (jenniferjuice):

So only inside the square root?

OpenStudy (anonymous):

yes

OpenStudy (jenniferjuice):

But that wouldnt produce a negative number in this case

OpenStudy (anonymous):

-20

OpenStudy (anonymous):

that's the discriminant

OpenStudy (anonymous):

Quick question, what module is your exam on?

OpenStudy (jenniferjuice):

The module is 3

OpenStudy (jenniferjuice):

and -2^2 + 4(2)(3) is 29

OpenStudy (anonymous):

oh, ok. I thought this was 5. 29 hmmm... actually 28 but that means you need to change your equation. That's the correct formula.

OpenStudy (anonymous):

change the equation to: -2x^2 -3x + 3 = 0 -b+4ac

OpenStudy (anonymous):

The discriminant is -15

OpenStudy (anonymous):

sorry no -b it's b-4ac

OpenStudy (anonymous):

b^2-4ac stupid typo

OpenStudy (jenniferjuice):

Okay, so find a set of numbers to plug into the forula and get a negative output?

OpenStudy (anonymous):

yes. This should give you a negative output: -2x^2 -3x + 3 = 0

OpenStudy (jenniferjuice):

I got 40

OpenStudy (jenniferjuice):

i was going to use a =2, b = 2, and c = 1

OpenStudy (anonymous):

Don't copy this but read it and it should give you a idea of how to solve the equation. This is my answer from my test.

OpenStudy (anonymous):

Even not real numbers need a solution. Here's an equation x^2-2x+5=0. Plug these in into the discriminant and see what we up to. -16 is my discriminant so it's a complex solution. Now let's find the solution. No greatest common factor so plug it in into the quadratic formula. -b plus or minus sq root b -4ac/2a. -(-2) plus or minus sq root (-2)^2+4(1)(5)/2(1). Now simplify, 2 plus or minus sq root -16/2 you can't have a negative sq root so you take sq root i or -1 times sq root 16. 16 is a perfect square so it's 4 and you combine i with 4 and divide 2 and 4i. Which you'll get 1 plus or minus 2i.

OpenStudy (anonymous):

I got a 10 on the question so its correct

OpenStudy (jenniferjuice):

Thank you, ill use a new equation and solve it using the method you used.

OpenStudy (anonymous):

kk, goodluck on the others

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