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Mathematics 8 Online
OpenStudy (anonymous):

Find The Radius, When The Sector Area Is 66.99. (Let Me Attach The File)

OpenStudy (anonymous):

Here's The Picture

jimthompson5910 (jim_thompson5910):

How much of the circle has been filled up?

jimthompson5910 (jim_thompson5910):

In terms of a fraction or percentage

OpenStudy (anonymous):

My Question Is Just To Find The Radius

jimthompson5910 (jim_thompson5910):

I know

jimthompson5910 (jim_thompson5910):

120 degrees is what fraction of a full revolution?

OpenStudy (anonymous):

120 over 360

jimthompson5910 (jim_thompson5910):

120/360 = 1/3

jimthompson5910 (jim_thompson5910):

so 1/3 of the circle is filled in which means 1/3 = 66.99/x x = ??

OpenStudy (anonymous):

@jim_thompson5910 so i cross multiply next to get x

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (anonymous):

there's a missing number for the cross multiply

jimthompson5910 (jim_thompson5910):

1/3 = 66.99/x 1*x = 3*66.99 x = ??

OpenStudy (anonymous):

200.97

jimthompson5910 (jim_thompson5910):

That's the area of the full circle

jimthompson5910 (jim_thompson5910):

Now use this formula A = pi*r^2 to get the radius

OpenStudy (anonymous):

u lost me

jimthompson5910 (jim_thompson5910):

A = pi*r^2 is the area of any circle

jimthompson5910 (jim_thompson5910):

A = 200.97 in this case

jimthompson5910 (jim_thompson5910):

A = pi*r^2 200.97 = pi*r^2 r = ??

OpenStudy (anonymous):

so divide each side by 3.14

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

then take the square root of both sides to isolate r

OpenStudy (anonymous):

help me out on that

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

what do you get so far

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