Mathematics
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OpenStudy (anonymous):
Find The Radius, When The Sector Area Is 66.99. (Let Me Attach The File)
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OpenStudy (anonymous):
Here's The Picture
jimthompson5910 (jim_thompson5910):
How much of the circle has been filled up?
jimthompson5910 (jim_thompson5910):
In terms of a fraction or percentage
OpenStudy (anonymous):
My Question Is Just To Find The Radius
jimthompson5910 (jim_thompson5910):
I know
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jimthompson5910 (jim_thompson5910):
120 degrees is what fraction of a full revolution?
OpenStudy (anonymous):
120 over 360
jimthompson5910 (jim_thompson5910):
120/360 = 1/3
jimthompson5910 (jim_thompson5910):
so 1/3 of the circle is filled in
which means
1/3 = 66.99/x
x = ??
OpenStudy (anonymous):
@jim_thompson5910 so i cross multiply next to get x
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jimthompson5910 (jim_thompson5910):
correct
OpenStudy (anonymous):
there's a missing number for the cross multiply
jimthompson5910 (jim_thompson5910):
1/3 = 66.99/x
1*x = 3*66.99
x = ??
OpenStudy (anonymous):
200.97
jimthompson5910 (jim_thompson5910):
That's the area of the full circle
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jimthompson5910 (jim_thompson5910):
Now use this formula
A = pi*r^2
to get the radius
OpenStudy (anonymous):
u lost me
jimthompson5910 (jim_thompson5910):
A = pi*r^2 is the area of any circle
jimthompson5910 (jim_thompson5910):
A = 200.97 in this case
jimthompson5910 (jim_thompson5910):
A = pi*r^2
200.97 = pi*r^2
r = ??
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OpenStudy (anonymous):
so divide each side by 3.14
jimthompson5910 (jim_thompson5910):
correct
jimthompson5910 (jim_thompson5910):
then take the square root of both sides to isolate r
OpenStudy (anonymous):
help me out on that
OpenStudy (anonymous):
@jim_thompson5910
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jimthompson5910 (jim_thompson5910):
what do you get so far