Question

Please explain how to find the vertex for this problem.
f(x)=(x+2)^2+9

Answer 1

http://www.mathwarehouse.com/geometry/parabola/images/standard-vertex-forms-thumb.png <--- can you see the vertex coordinates?

Answer 2

\(\bf f(x)=(x+2)^2+9\implies f(x)=[x-({\color{blue}{ -2}})]^2{\color{purple}{ +9}}\)

Answer 3

Yes, I can see them

Answer 4

so is the vertex (2,-9)? Or (-2,9)?

Answer 5

f(x)=(x+2)^2+9..Make this into a quadratic equation ax^2+bx+c..The vertex for the x corinate is determined by the formula x=-b/2a,

Answer 6

Okay, thank you!