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help! "What is the period, in seconds, of a simple pendulum of length 2 meters? Use the gravitational constant g = 9.8 m/s^2 and round your answer to two decimal places.
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what do you know?
that the pendulum is 2 meters long
how do you solve for the period?
\[T = 2 \pi \sqrt{\frac{L}{g}}\] L length of pendulum g gravitational constant
using a calculator i got 2.838 which i guess rounds to 2.84
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for your answer to be a correct approximation you will need to make sure you have the proper significant figures 2.00 meters 9.80 m/s^2 that is the only way you will be able to justify to a hundredth degree precision
that seems correct
good day
and good day to you, nincompoop!
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