Which situation would cause the following equilibrium reaction to shift to the right? N2O4 (g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. 2 NO2 (g) increase the pressure remove N2O4 remove NO2 decrease the volume
@iPwnBunnies
what you say...? @superhelp101
i think remove NO2 because of a theory i can't remember what it was called
how?
Le Châtelier’s principle....?
yes that is the one i am taking about :)
hmmm rite... so then...?
huh ? is it right ?
yeah
yay thanks for checking!!
pleasure...
According to Le Chatelier, the position of equilibrium will move in such a way as to counteract the change. That means that the position of equilibrium will move so that the pressure is reduced again. Pressure is caused by gas molecules hitting the sides of their container. The more molecules you have in the container, the higher the pressure will be. The system can reduce the pressure by reacting in such a way as to produce fewer molecules. According to Le Chatelier, the position of equilibrium will move so that the concentration of N2O4 increases again. That means that more NO2 will decompose to replace the N2O4 that has been removed. The position of equilibrium moves to the left. i think if volume decreased pressure will increase as there is less space occupied by molecules therefore would collide more exerting a greater force and pressure and its the same thing when increasing pressure
thank you soooo much!
your most welcome :D :)
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