Ask your own question, for FREE!
Chemistry 22 Online
OpenStudy (superhelp101):

All of the following can be used to define a base except a hydronium ion donor in a reaction a substance that increases the concentration of hydroxide ions an electron pair donor in a reaction a substance that is a hydrogen ion acceptor in a reaction

OpenStudy (paki):

what you say...?

OpenStudy (superhelp101):

i think it is hydronium ion donor in a reaction but i not sure...

OpenStudy (paki):

@MacAttack123315 what you say here...?

OpenStudy (paki):

you are rite... but can you explain...?

OpenStudy (anonymous):

In my chemistry book, it defines a Bronsted-Lowry base as a hydrogen-ion acceptor

OpenStudy (superhelp101):

yeah so i think it is because of Bronsted-Lowry concept :)

OpenStudy (anonymous):

So I'd say the 4th option haha

OpenStudy (paki):

OH- + H3O+ -> H2O + H2O Base | Acid | Conjugate Acid | Conjugate Base (Normally the product would be written just as 2H2O)

OpenStudy (abmon98):

When hydrogen chloride dissolves in water, almost 100% of it reacts with the water to produce hydroxonium ions and chloride ions. Hydrogen chloride is a strong acid, and we tend to write this as a one-way reaction: HCl+H2Oequilbrium signH3O+Cl- An acid is a proton (hydrogen ion) donor. A base is a proton (hydrogen ion) acceptor. think about Hydrogen is donated from the HCl to H2O if the reaction is reversed a hydrogen is donated from H3O to Cl-

OpenStudy (abmon98):

yes bases can provide both electrons in a reaction for a coordinate bond. NH3+HCl--->NH4CL it provides both its electrons to bond with the H+ ion to form NH4+Cl-

OpenStudy (abmon98):

lone pair of electrons(not involved in the reaction)

OpenStudy (abmon98):

i go with A so you are right @superhelp101 , good job :)

OpenStudy (superhelp101):

very helpful!! @Abmon98 thank all of you @paki @MacAttack123315

OpenStudy (anonymous):

ohhh except? haha I didn't see that part

OpenStudy (anonymous):

yeah so 1st option

OpenStudy (paki):

pleasure...

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!