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integrate sqrt(e^x) dx
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sqrt(e^x) dx=e^{x/2} Got the idea?
why not apply index laws and make it \[\int\limits e^{\frac{1}{2} x} dx\]
@campbell_st then ?
well isn't it \[\int\limits e^{\frac{x}{2}} dx = 2e^\frac{x}{2} + C\] you can differentiate to check
thanks @campbell_st
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Put e^x = u then e^x dx = du dx = (1/u) du
Another possible substitution, \(y=\sqrt e^x\), so \(y^2=e^x\) and \(dy=\dfrac{e^x}{2\sqrt e^x}~dx\), which gives the same outcome as @midhun.madhu1987's suggestion.
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