what is the relation between fourier transform and phasor?

Question

sidsiddhartha · Answer

fourier transform is a special type of integral transform by which we can take any time domain function into frequency domain.
it is a special case of bilateral laplace transform 
$$F[f(t)]=F(jw)=\int\limits_{-\infty}^{\infty}f(t) *e^{-jwt}dt$$

phasor, is a complex number representing a sinusoidal function whose amplitude (A), frequency (ω), and phase (θ) are time-invariant.

sidsiddhartha · Answer

and i'm not sure, what do u mean by relationship between them?

ybarrap · Answer

Using @sidsiddhartha's integral representing the Fourier transform, the relationship is that $F(jw)$ is the original function, f(t) weighted by a phasor $e^{-jwt}$, at each instant of time, t, summed (i.e. integrated) over all time.

So the Fourier transform is essentially a phasor-weighted sum.