Question

Why is radical25 not equal to -5?

Answer 1

because 25 is not a variable.

Answer 2

\(\normalsize\color{black}{ \sqrt{25} }\) can be equal to \(\normalsize\color{black}{ 5 }\) or \(\normalsize\color{black}{ -5 }\).

Answer 3

no , \[\sqrt{25}\] only can be equal for +5

Answer 4

No

Answer 5

\(\normalsize\color{black}{ \sqrt{25}=±5 }\) (Since, you know that \(\normalsize\color{black}{ (-5)^2=25 }\) and \(\normalsize\color{black}{ 5^2=25 }\) .

Answer 6

You are confusing 2 different concepts.

A square root of a number (if the number is positive) has 2 real values, like
\(\normalsize\color{black}{ \sqrt{36}=±6 \color{white}{\Large()ccc}}\)
\(\normalsize\color{black}{ \sqrt{25}=±5 \color{white}{\Large()ccc} }\)
\(\normalsize\color{black}{ \sqrt{16}=±4 \color{white}{\Large()ccc}}\)
\(\normalsize\color{black}{ \sqrt{9}~~~=±3\color{white}{\Large()ccc} }\)
\(\normalsize\color{black}{ \sqrt{4}~~~=±2\color{white}{\Large()ccc} }\)
\(\normalsize\color{black}{ \sqrt{1}~~~=±1\color{white}{\Large()ccc} }\)

Answer 7

And the other concept that there is no such a thing as \(\normalsize\color{black}{ \sqrt{-b} }\)

Answer 8

(in terms of a real number solution)

Answer 9

well may be you right, but my maths teacher taught me something like this.

if x^2 = 25
then x =- or + \[\sqrt{25}\]
and then x = - or + 5

this means \[\sqrt{25}\] = 5

thats why i'm disagree with you