The slope of a line is –4 and its y-intercept is (0, 4). What is the equation of the line that is perpendicular to the first line and passes through (–8, 2)?
I'm going to tell you about these kinds of problems. For this particular situation, you want to find out what makes a line perpendicular and how do you find it. The answer is all about SLOPE. First, you'd want to find point slope form for the first line.
@Tara03 Do you remember from our other question how to put that first line into point form?
yeah I know we have to plug in it -4=m and slope but the perpendicular part throws me off
So what is the point slope form?
I'll guide you through the perpendicular part.
i just get confused with setting it up right but i know we can simplify it down so we can get it in slope point form. so cant we get rid of the 0 in (0,4) and just have 4?
In this situation yes, but in order for me to show you. I'll walk you through it :)
Point slope form of the line if m = -4 and the y intercept is (0,4) is y-4 = -4(x-0) The SLOPE is the key to the perpendicular. When looking for the equation of the perpendicular line, LEAVE IT in point slope form :)
The key in all of this for the perpendicular line is that a perpendicular line is your point slope form line except that the slope is the negative reciprocal. Do you understand what I mean by that? Like in this case of m = -4, the negative reciprocal is 1/4
right I have a question though this is where I get confused is when we are seeing if its perpendicular or not. can it still be perpendicular if one line is 1/4 and the other is -1/4?
|dw:1406910327122:dw| You mean like this?
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