Question

find the general form of the equation of a line if it passes through the points

a) (1,2) and (3,4)

b) (1,3) and (2,5)

c) (-1,2) and (-3,-5)

d) (-2,4) and (3,4)

e) (0,0) and (5,8)

f) (2,2) and (5,5)

Answer 1

it like 3 in the morning and i have another booklet and 2 pages to go please help

Answer 2

if i dont hand it in by 1 im dead

Answer 3

if the points are (x1 , x2) & (y1 & y2) then general form is :
(y-y1)/(y2-y1) = (x-x1)/(x2-x1)

Answer 4

i think so

Answer 5

ok. I will solve first one for you. and you have to find other solutions using the way I solved.
so the points are (1,2) and (3,4)
these points must be on the solution
to find the solution I will use this method

\[\frac{ y -2 }{ x - 1 } = \frac{ 2 - 4 }{ 1 -3 }\]

Answer 6

by simplifying you will get y = x +1