The natural frequency of rod A is 1/2 times the natural frequency of rod B for
longitudinal vibrations. If the rods have the same geometry and ρA = 2ρB, then the
ratio of Young's moduli for A to B is:
a. SQR RT [2]
b. 2
c. 4
d. 1/SQR RT [2]
e. 1/2

Question

The natural frequency of rod A is 1/2 times the natural frequency of rod B for
longitudinal vibrations. If the rods have the same geometry and ρA = 2ρB, then the
ratio of Young's moduli for A to B is:
a. SQR RT [2]
b. 2
c. 4
d. 1/SQR RT [2]
e. 1/2

anonymous · Answer

$$f _{a}/f _{b}=\sqrt{Y _{a}/\rho a / Yb / \rho b}$$

my answer is coming e but answer key showing c is correct how ?

anonymous · Answer

@Mashy  @ParthKohli  @SolomonZelman

anonymous · Answer

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