Question

Jesse kicks a soccer ball off the ground and in the air, with an initial velocity of 29 feet per second. Using the formula H(t) = -16t2 + vt + s, what is the maximum height the soccer ball reaches?


13.1 feet

13.5 feet

13.8 feet

14.2 feet

Answer 1

+s? can you recheck the given forumla?

Answer 2

Yep, this it @study100

Answer 3

@study100 Please help!

Answer 4

Alright, you can solve this by plug t= 0 and h(t) = 0 to the equation
height = 0 at time = 0
and they say that initial velocity is 29. v= 29
0= 0 + 0 +s
s= 0

now you can eliminate s out from the equation
we just have
H(t) = -16t^2+ vt

Answer 5

Alright

Answer 6

What math level is this?
then you plug v=29 into the equation
H(t) = -16t^2 +29t

Now look at NUMBER 1 on this: http://www.wikihow.com/Find-the-Maximum-or-Minimum-Value-of-a-Quadratic-Function-Easily

so, to find H(t) max you'd take this equation
y= c- b^2/4a

H(t) = 0- 29^2 / 4(-16)
H(t) = -841/-64
H(t) = ?
find out

Answer 7

13.140625

Answer 8

Yes, which rounds to 13.1

Answer 9

Ye3