Question

Task 4—Solving Rational Equations
Using the equation below as a model, fill in numbers in the place of a and b to create a rational equation that has an extraneous solution.

Part 1. Show all work to solve for x in the equation and check the solution.
Part 2. Explain how to identify the extraneous solution and what it means.
Part 3. Use complete sentences to explain how the remainder theorem is used to determine whether your linear binomial is a factor of your polynomial function

Answer 1

@Nurali

Answer 2

Help

Answer 3

@superRbow15

Answer 4

@ikram002p

Answer 5

@phi

Answer 6

Phi please help me

Answer 7

You have to do this

Using the equation below as a model, fill in numbers in the place of a and b to create a rational equation that has an extraneous solution.

What equation do they show you?

Answer 8

None, you have to make one

Answer 9

Using the equation below as a model<--- ??

Answer 10

Oh wait they do, give me a sec

Answer 11

@phi

Answer 12

they say
fill in numbers in the place of a and b
where is "b" ?

Answer 13

X = b here

Answer 14

They didn't design the course correctly and it has errors

Answer 15

do you mean
\[ \frac{x+a}{ax} = b \]?

Answer 16

so far, you have not posted an equation with a and b in it.

Answer 17

can you find and post the "model equation"?

Answer 18

@phi I am so sorry my father wanted me to get him something from the store

Answer 19

x plus a over ax = b over x
\[ \frac{ x+ a }{ ax } = \frac{ b }{ x}\]

Answer 20

DONE!

Answer 21

Can we use this @phi

Answer 22

yes, but they want you to replace a and b with numbers

Answer 23

So, can I put random numbers?

Answer 24

\frac{ x+ 1 }{ (1)x } = \frac{ 2 }{ x}

Answer 25

\[\frac{ X + 1 }{ 1(x) } = \frac{ 2 }{ x }\]

Answer 26

ok, a=1 and b=2
\[ \frac{ x+ 1 }{ (1)x } = \frac{ 2 }{ x} \]

Answer 27

Yep

Answer 28

we could cross multiply to get
x(x+1) = 2x
x^2 + x = 2x
x^2 -x = 0
x(x-1)=0
x=0 or x=1

the x=0 is extraneous, because we are not allowed to divide by 0
(which is what happens in the original equation if x is 0)

Answer 29

Is dis de answer?

Answer 30

yes