Question

Find the equation of a circle that has its center at (-4, 3) and has a radius of 5.
(x + 4) ^2 + (y - 3) ^2 = 25

(x - 4) ^2 + (y - 3) ^2 = 25

(x + 4) ^2 + (y + 3) ^2 = 25

(x - 4) ^2 + (y + 3) ^2 = 25

Answer 1

hint:

(x-h)^2+(y-k)^2=r^2

is a circle with center (h,k) and radius r

Answer 2

so the last one

Answer 3

\(\bf (x-{\color{green}{ h}})^2+(y-{\color{purple}{ k}})={\color{olive}{ r}}^2\qquad center\ ({\color{green}{ h}}, {\color{purple}{ k}})\quad radius = {\color{olive}{ r}}\)

Answer 4

(x - 4) ^2 + (y + 3) ^2 = 25

is really

(x - 4) ^2 + (y - (-3)) ^2 = 5^2

so

h = 4
k = -3
r = 5

Center: (4,-3)
Radius: 5

Answer 5

So the center is off for choice D

Answer 6

\(\bf (x-{\color{green}{ h}})^2+(y-{\color{purple}{ k}})={\color{olive}{ r}}^2\qquad center\ ({\color{green}{ -4}}, {\color{purple}{ 3}})\quad radius = {\color{olive}{ 5}}\)