Question

if tan thetA=a/b then the value of a sin theta +b cos theta/a sin theta-b cos theta=

Answer 1

theta=x
sinx/cosx=a/b

Answer 2

a *a+b *b/a*a-b*b

Answer 3

a^2+b^2/a^2-b^2

Answer 4

@Mandre

Answer 5

@theEric

Answer 6

\[\frac{ a \sin \theta + b \cos \theta }{ a \sin \theta - b \cos \theta }\]
divide both numerator and denominator by \(\cos \theta\) and put the value of \(\tan\theta\)

Answer 7

a^2/b+1/a^2/b-1

Answer 8

a^2+b/a^2-b

Answer 9

same i done above

Answer 10

\[\frac{ \frac{ a^2 }{ b }+b }{ \frac{ a^2 }{ b }-b }\]

Answer 11

and then..(a^2+b^2)/(a^2-b^2)

Answer 12

@souvik i have done that earlier see at the top

Answer 13

Just because I'm a fan of fancy tricks.\[\dfrac{\sin\theta}{\cos\theta} = \dfrac{a}{b}\]\[\dfrac{a\sin\theta}{b\cos\theta} = \dfrac{a^2}{b^2}\]Applying C&D to both sides,\[\dfrac{a\sin\theta + b\cos\theta}{a\sin\theta - b\cos\theta } = \dfrac{a^2 + b^2}{a^2 - b^2}\]

Answer 14

clever+cute xD

Answer 15

after that i have done that earlier in 3rd step

Answer 16

see it required two steps.after that

Answer 17

oh thats the final answer ahh

Answer 18

yes if u believe in C&D :)

Answer 19

oh got it before itself.see i used theta =x for my convenience

Answer 20

theta=x sinx/cosx=a/b

Answer 21

a *a+b *b/a*a-b*b

Answer 22

a^2+b^2/a^2-b^2

Answer 23

You guys all got it, congrats! :) Lots of individual team effort or something :)