Question

period of sin theta+sin 2 theta/cos theta+cos 2 theta

Answer 1

sin theta=90

Answer 2

sin 2 theta=45

Answer 3

90+45/360+180

Answer 4

\[\sin \theta+\cos 2 \theta/(\cos \theta+\cos 2\theta)\]

Answer 5

sorry in numerator sin 2theta

Answer 6

i thin sin x=2pi

Answer 7

the period of sinx is 2pi

Answer 8

so sin 2x=180

Answer 9

180+360/360+180=1

Answer 10

@dg2 just saying sin2x = 2sinxcosx

Answer 11

2*360*360

Answer 12

haha wish we could do all those crimes :D

Answer 13

^

Answer 14

sin 2x=180

Answer 15

\[\sin \theta +\sin 2 \theta /(\cos \theta+\cos 2\theta)\]

Answer 16

is it correct?

Answer 17

i got 1 as answer

Answer 18

\[\sin\theta + \sin2\theta = 2\sin(3\theta/2)\cos(\theta/2)\]\[\cos\theta + \cos2\theta = 2\cos(3\theta/2)\cos(\theta/2)\]Divide equations one and two,\[\cdots = \tan(3\theta/2)\]

Answer 19

The period of \(\tan(3\theta/2)\) can be easily determined.

Answer 20

sin 2x=2sinxcosx

Answer 21

2sinxcosx+sinx

Answer 22

how 3theta/2 in sin and cos @ParthKohli

Answer 23

I used these identities:\[\sin C + \sin D = 2\sin\left(\dfrac{C+D}{2}\right)\cos\left(\dfrac{C-D}{2}\right)\]\[\cos C + \cos D = 2\cos\left(\dfrac{C + D}{2}\right)\cos\left(\dfrac{C - D}{2}\right)\]

Answer 24

cos2x=2cos^2x-1=1-2sin^2x=cos^2x-sin^2x

Answer 25

ohh ok how to determine tan 3teta/2

Answer 26

OK, so you understood how I got \(\tan(3\theta/2)\) right?

I simplified your function to get \(\tan(3\theta/2)\). Do you know what the period of this is?

Answer 27

yes.tan 3a/2 formula?

Answer 28

Do you know what the period of \(\tan\) function is?

Answer 29

180

Answer 30

30

Answer 31

3*180/2

Answer 32

90/3

Answer 33

That's right, 180.

So \(\tan(3\theta/2)\) has period = 180 when \(3\theta/2 = 180\implies \theta = 2/3 \times 180 \).

Answer 34

120

Answer 35

120 or 30